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(3)=G^2+5G-8
We move all terms to the left:
(3)-(G^2+5G-8)=0
We get rid of parentheses
-G^2-5G+8+3=0
We add all the numbers together, and all the variables
-1G^2-5G+11=0
a = -1; b = -5; c = +11;
Δ = b2-4ac
Δ = -52-4·(-1)·11
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{69}}{2*-1}=\frac{5-\sqrt{69}}{-2} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{69}}{2*-1}=\frac{5+\sqrt{69}}{-2} $
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